Sr Examen

Expresión а&bvcv(a&c)⇒b

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (c∨(a∧b)∨(a∧c))⇒b
    $$\left(c \vee \left(a \wedge b\right) \vee \left(a \wedge c\right)\right) \Rightarrow b$$
    Solución detallada
    $$c \vee \left(a \wedge b\right) \vee \left(a \wedge c\right) = c \vee \left(a \wedge b\right)$$
    $$\left(c \vee \left(a \wedge b\right) \vee \left(a \wedge c\right)\right) \Rightarrow b = b \vee \neg c$$
    Simplificación [src]
    $$b \vee \neg c$$
    b∨(¬c)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    $$b \vee \neg c$$
    b∨(¬c)
    FNDP [src]
    $$b \vee \neg c$$
    b∨(¬c)
    FND [src]
    Ya está reducido a FND
    $$b \vee \neg c$$
    b∨(¬c)
    FNC [src]
    Ya está reducido a FNC
    $$b \vee \neg c$$
    b∨(¬c)