Expresión acbvnotc
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∧b∧c)∨¬c=(a∧b)∨¬c
(a∧b)∨¬c
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(a∨¬c)∧(b∨¬c)
Ya está reducido a FND
(a∧b)∨¬c
(a∨¬c)∧(b∨¬c)
(a∧b)∨¬c