Sr Examen
Expresión (pvq)^(!pvr)->(qvr)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
((p∨q)∧(r∨(¬p)))⇒(q∨r)
$$\left(\left(p \vee q\right) \wedge \left(r \vee \neg p\right)\right) \Rightarrow \left(q \vee r\right)$$
Solución detallada
$$\left(p \vee q\right) \wedge \left(r \vee \neg p\right) = \left(p \wedge r\right) \vee \left(q \wedge \neg p\right)$$
$$\left(\left(p \vee q\right) \wedge \left(r \vee \neg p\right)\right) \Rightarrow \left(q \vee r\right) = 1$$
$$\left(\left(p \vee q\right) \wedge \left(r \vee \neg p\right)\right) \Rightarrow \left(q \vee r\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | p | q | r | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+