Sr Examen
Expresión PvQvP^Q->!R
El profesor se sorprenderá mucho al ver tu solución correcta😉
⌨
Solución
Ha introducido
[src]
(p∨q∨(p∧q))⇒(¬r)
$$\left(p \vee q \vee \left(p \wedge q\right)\right) \Rightarrow \neg r$$
Solución detallada
$$p \vee q \vee \left(p \wedge q\right) = p \vee q$$
$$\left(p \vee q \vee \left(p \wedge q\right)\right) \Rightarrow \neg r = \left(\neg p \wedge \neg q\right) \vee \neg r$$
$$\left(p \vee q \vee \left(p \wedge q\right)\right) \Rightarrow \neg r = \left(\neg p \wedge \neg q\right) \vee \neg r$$
Tabla de verdad
+---+---+---+--------+ | p | q | r | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+
FNC
[src]
$$\left(\neg p \vee \neg r\right) \wedge \left(\neg q \vee \neg r\right)$$
((¬p)∨(¬r))∧((¬q)∨(¬r))
FNCD
[src]
$$\left(\neg p \vee \neg r\right) \wedge \left(\neg q \vee \neg r\right)$$
((¬p)∨(¬r))∧((¬q)∨(¬r))