Expresión x->(y->z)->(x&y->z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
y⇒z=z∨¬yx⇒(y⇒z)=z∨¬x∨¬y(x∧y)⇒z=z∨¬x∨¬y(x⇒(y⇒z))⇒((x∧y)⇒z)=1
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+