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Lógica matemática/ ¬xyt+xyzt

Expresión ¬xyt+xyzt

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    (t∧y∧(¬x))∨(t∧x∧y∧z)
    $$\left(t \wedge y \wedge \neg x\right) \vee \left(t \wedge x \wedge y \wedge z\right)$$
    Solución detallada
    $$\left(t \wedge y \wedge \neg x\right) \vee \left(t \wedge x \wedge y \wedge z\right) = t \wedge y \wedge \left(z \vee \neg x\right)$$
    Simplificación [src]
    $$t \wedge y \wedge \left(z \vee \neg x\right)$$ 
    t∧y∧(z∨(¬x))
    Tabla de verdad 
    +---+---+---+---+--------+
| t | x | y | z | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FNCD [src]
    $$t \wedge y \wedge \left(z \vee \neg x\right)$$ 
    t∧y∧(z∨(¬x))
    FND [src]
    $$\left(t \wedge y \wedge z\right) \vee \left(t \wedge y \wedge \neg x\right)$$ 
    (t∧y∧z)∨(t∧y∧(¬x))
    FNC [src]
    Ya está reducido a FNC
    $$t \wedge y \wedge \left(z \vee \neg x\right)$$ 
    t∧y∧(z∨(¬x))
    FNDP [src]
    $$\left(t \wedge y \wedge z\right) \vee \left(t \wedge y \wedge \neg x\right)$$ 
    (t∧y∧z)∨(t∧y∧(¬x))
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