Expresión CA∨¬(CAB→(¬BA⇔CB))⇔CA∨B¬A
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Solución
Solución detallada
$$\left(a \wedge \neg b\right) ⇔ \left(b \wedge c\right) = \left(b \wedge \neg c\right) \vee \left(\neg a \wedge \neg b\right)$$
$$\left(a \wedge b \wedge c\right) \Rightarrow \left(\left(a \wedge \neg b\right) ⇔ \left(b \wedge c\right)\right) = \neg a \vee \neg b \vee \neg c$$
$$\left(a \wedge b \wedge c\right) \not\Rightarrow \left(\left(a \wedge \neg b\right) ⇔ \left(b \wedge c\right)\right) = a \wedge b \wedge c$$
$$\left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right) \not\Rightarrow \left(\left(a \wedge \neg b\right) ⇔ \left(b \wedge c\right)\right) = a \wedge c$$
$$\left(\left(a \wedge c\right) \vee \left(b \wedge \neg a\right)\right) ⇔ \left(\left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right) \not\Rightarrow \left(\left(a \wedge \neg b\right) ⇔ \left(b \wedge c\right)\right)\right) = a \vee \neg b$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FND
$$a \vee \neg b$$
Ya está reducido a FNC
$$a \vee \neg b$$