Sr Examen

Expresión CA∨¬(CAB→(¬BA⇔CB))⇔CA∨B¬A

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ((a∧c)∨(b∧(¬a)))⇔((a∧c)∨(¬((a∧b∧c)⇒((b∧c)⇔(a∧(¬b))))))
    ((ac)(b¬a))((ac)(abc)⇏((a¬b)(bc)))\left(\left(a \wedge c\right) \vee \left(b \wedge \neg a\right)\right) ⇔ \left(\left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right) \not\Rightarrow \left(\left(a \wedge \neg b\right) ⇔ \left(b \wedge c\right)\right)\right)
    Solución detallada
    (a¬b)(bc)=(b¬c)(¬a¬b)\left(a \wedge \neg b\right) ⇔ \left(b \wedge c\right) = \left(b \wedge \neg c\right) \vee \left(\neg a \wedge \neg b\right)
    (abc)((a¬b)(bc))=¬a¬b¬c\left(a \wedge b \wedge c\right) \Rightarrow \left(\left(a \wedge \neg b\right) ⇔ \left(b \wedge c\right)\right) = \neg a \vee \neg b \vee \neg c
    (abc)⇏((a¬b)(bc))=abc\left(a \wedge b \wedge c\right) \not\Rightarrow \left(\left(a \wedge \neg b\right) ⇔ \left(b \wedge c\right)\right) = a \wedge b \wedge c
    (ac)(abc)⇏((a¬b)(bc))=ac\left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right) \not\Rightarrow \left(\left(a \wedge \neg b\right) ⇔ \left(b \wedge c\right)\right) = a \wedge c
    ((ac)(b¬a))((ac)(abc)⇏((a¬b)(bc)))=a¬b\left(\left(a \wedge c\right) \vee \left(b \wedge \neg a\right)\right) ⇔ \left(\left(a \wedge c\right) \vee \left(a \wedge b \wedge c\right) \not\Rightarrow \left(\left(a \wedge \neg b\right) ⇔ \left(b \wedge c\right)\right)\right) = a \vee \neg b
    Simplificación [src]
    a¬ba \vee \neg b
    a∨(¬b)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    a¬ba \vee \neg b
    a∨(¬b)
    FND [src]
    Ya está reducido a FND
    a¬ba \vee \neg b
    a∨(¬b)
    FNC [src]
    Ya está reducido a FNC
    a¬ba \vee \neg b
    a∨(¬b)
    FNCD [src]
    a¬ba \vee \neg b
    a∨(¬b)