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Expresión (av¬bv((a&b)vc)v(a&(¬avb)))vbvc

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    a∨b∨c∨(¬b)∨(a∧b)∨(a∧(b∨(¬a)))
    abc(ab)(a(b¬a))¬ba \vee b \vee c \vee \left(a \wedge b\right) \vee \left(a \wedge \left(b \vee \neg a\right)\right) \vee \neg b
    Solución detallada
    a(b¬a)=aba \wedge \left(b \vee \neg a\right) = a \wedge b
    abc(ab)(a(b¬a))¬b=1a \vee b \vee c \vee \left(a \wedge b\right) \vee \left(a \wedge \left(b \vee \neg a\right)\right) \vee \neg b = 1
    Simplificación [src]
    1
    1
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    1
    1
    FNDP [src]
    1
    1
    FND [src]
    Ya está reducido a FND
    1
    1
    FNC [src]
    Ya está reducido a FNC
    1
    1