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Lógica matemática/ ¬A&¬BvC&A&BvDv¬D&C

Expresión ¬A&¬BvC&A&BvDv¬D&C

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    d∨(c∧(¬d))∨(a∧b∧c)∨((¬a)∧(¬b))
    d∨(c∧¬d)∨(¬a∧¬b)∨(a∧b∧c)d \vee \left(c \wedge \neg d\right) \vee \left(\neg a \wedge \neg b\right) \vee \left(a \wedge b \wedge c\right)
    Solución detallada
    d∨(c∧¬d)∨(¬a∧¬b)∨(a∧b∧c)=c∨d∨(¬a∧¬b)d \vee \left(c \wedge \neg d\right) \vee \left(\neg a \wedge \neg b\right) \vee \left(a \wedge b \wedge c\right) = c \vee d \vee \left(\neg a \wedge \neg b\right)
    Simplificación [src]
    c∨d∨(¬a∧¬b)c \vee d \vee \left(\neg a \wedge \neg b\right) 
    c∨d∨((¬a)∧(¬b))
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FNC [src]
    (c∨d∨¬a)∧(c∨d∨¬b)\left(c \vee d \vee \neg a\right) \wedge \left(c \vee d \vee \neg b\right) 
    (c∨d∨(¬a))∧(c∨d∨(¬b))
    FNDP [src]
    c∨d∨(¬a∧¬b)c \vee d \vee \left(\neg a \wedge \neg b\right) 
    c∨d∨((¬a)∧(¬b))
    FNCD [src]
    (c∨d∨¬a)∧(c∨d∨¬b)\left(c \vee d \vee \neg a\right) \wedge \left(c \vee d \vee \neg b\right) 
    (c∨d∨(¬a))∧(c∨d∨(¬b))
    FND [src]
    Ya está reducido a FND
    c∨d∨(¬a∧¬b)c \vee d \vee \left(\neg a \wedge \neg b\right) 
    c∨d∨((¬a)∧(¬b))
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