Sr Examen

Expresión ¬c&a&¬bva&c

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧c)∨(a∧(¬b)∧(¬c))
    (ac)(a¬b¬c)\left(a \wedge c\right) \vee \left(a \wedge \neg b \wedge \neg c\right)
    Solución detallada
    (ac)(a¬b¬c)=a(c¬b)\left(a \wedge c\right) \vee \left(a \wedge \neg b \wedge \neg c\right) = a \wedge \left(c \vee \neg b\right)
    Simplificación [src]
    a(c¬b)a \wedge \left(c \vee \neg b\right)
    a∧(c∨(¬b))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    (ac)(a¬b)\left(a \wedge c\right) \vee \left(a \wedge \neg b\right)
    (a∧c)∨(a∧(¬b))
    FNCD [src]
    a(c¬b)a \wedge \left(c \vee \neg b\right)
    a∧(c∨(¬b))
    FNC [src]
    Ya está reducido a FNC
    a(c¬b)a \wedge \left(c \vee \neg b\right)
    a∧(c∨(¬b))
    FNDP [src]
    (ac)(a¬b)\left(a \wedge c\right) \vee \left(a \wedge \neg b\right)
    (a∧c)∨(a∧(¬b))