Sr Examen
Expresión ¬(avb⇒¬(bvc))
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
¬((a∨b)⇒(¬(b∨c)))
$$\left(a \vee b\right) \not\Rightarrow \neg \left(b \vee c\right)$$
Solución detallada
$$\neg \left(b \vee c\right) = \neg b \wedge \neg c$$
$$\left(a \vee b\right) \Rightarrow \neg \left(b \vee c\right) = \neg b \wedge \left(\neg a \vee \neg c\right)$$
$$\left(a \vee b\right) \not\Rightarrow \neg \left(b \vee c\right) = b \vee \left(a \wedge c\right)$$
$$\left(a \vee b\right) \Rightarrow \neg \left(b \vee c\right) = \neg b \wedge \left(\neg a \vee \neg c\right)$$
$$\left(a \vee b\right) \not\Rightarrow \neg \left(b \vee c\right) = b \vee \left(a \wedge c\right)$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+