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Lógica matemática/ AD∨C¬D+¬BD

Expresión AD∨C¬D+¬BD

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    (a∧d)∨(c∧(¬d))∨(d∧(¬b))
    $$\left(a \wedge d\right) \vee \left(c \wedge \neg d\right) \vee \left(d \wedge \neg b\right)$$
    Simplificación [src]
    $$\left(a \wedge d\right) \vee \left(c \wedge \neg d\right) \vee \left(d \wedge \neg b\right)$$ 
    (a∧d)∨(c∧(¬d))∨(d∧(¬b))
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FNC [src]
    $$\left(c \vee d\right) \wedge \left(d \vee \neg d\right) \wedge \left(a \vee c \vee d\right) \wedge \left(a \vee c \vee \neg b\right) \wedge \left(a \vee d \vee \neg d\right) \wedge \left(a \vee \neg b \vee \neg d\right) \wedge \left(c \vee d \vee \neg b\right) \wedge \left(d \vee \neg b \vee \neg d\right)$$ 
    (c∨d)∧(d∨(¬d))∧(a∨c∨d)∧(a∨c∨(¬b))∧(a∨d∨(¬d))∧(c∨d∨(¬b))∧(a∨(¬b)∨(¬d))∧(d∨(¬b)∨(¬d))
    FND [src]
    Ya está reducido a FND
    $$\left(a \wedge d\right) \vee \left(c \wedge \neg d\right) \vee \left(d \wedge \neg b\right)$$ 
    (a∧d)∨(c∧(¬d))∨(d∧(¬b))
    FNCD [src]
    $$\left(c \vee d\right) \wedge \left(a \vee \neg b \vee \neg d\right)$$ 
    (c∨d)∧(a∨(¬b)∨(¬d))
    FNDP [src]
    $$\left(a \wedge d\right) \vee \left(c \wedge \neg d\right) \vee \left(d \wedge \neg b\right)$$ 
    (a∧d)∨(c∧(¬d))∨(d∧(¬b))
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