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Lógica matemática/ DC¬BA+DCB

Expresión DC¬BA+DCB

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    Solución

    Ha introducido [src] 
    (b∧c∧d)∨(a∧c∧d∧(¬b))
    $$\left(b \wedge c \wedge d\right) \vee \left(a \wedge c \wedge d \wedge \neg b\right)$$
    Solución detallada
    $$\left(b \wedge c \wedge d\right) \vee \left(a \wedge c \wedge d \wedge \neg b\right) = c \wedge d \wedge \left(a \vee b\right)$$
    Simplificación [src]
    $$c \wedge d \wedge \left(a \vee b\right)$$ 
    c∧d∧(a∨b)
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FNDP [src]
    $$\left(a \wedge c \wedge d\right) \vee \left(b \wedge c \wedge d\right)$$ 
    (a∧c∧d)∨(b∧c∧d)
    FND [src]
    $$\left(a \wedge c \wedge d\right) \vee \left(b \wedge c \wedge d\right)$$ 
    (a∧c∧d)∨(b∧c∧d)
    FNCD [src]
    $$c \wedge d \wedge \left(a \vee b\right)$$ 
    c∧d∧(a∨b)
    FNC [src]
    Ya está reducido a FNC
    $$c \wedge d \wedge \left(a \vee b\right)$$ 
    c∧d∧(a∨b)
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