Sr Examen
Expresión ¬((x¬yz+¬xy¬z)+(x+y))
El profesor se sorprenderá mucho al ver tu solución correcta😉
⌨
Solución
Ha introducido
[src]
¬(x∨y∨(x∧z∧(¬y))∨(y∧(¬x)∧(¬z)))
$$\neg \left(x \vee y \vee \left(x \wedge z \wedge \neg y\right) \vee \left(y \wedge \neg x \wedge \neg z\right)\right)$$
Solución detallada
$$x \vee y \vee \left(x \wedge z \wedge \neg y\right) \vee \left(y \wedge \neg x \wedge \neg z\right) = x \vee y$$
$$\neg \left(x \vee y \vee \left(x \wedge z \wedge \neg y\right) \vee \left(y \wedge \neg x \wedge \neg z\right)\right) = \neg x \wedge \neg y$$
$$\neg \left(x \vee y \vee \left(x \wedge z \wedge \neg y\right) \vee \left(y \wedge \neg x \wedge \neg z\right)\right) = \neg x \wedge \neg y$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+