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Lógica matemática/ ¬C→(A∨(B∨C⋅B))

Expresión ¬C→(A∨(B∨C⋅B))

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    Solución

    Ha introducido [src] 
    (¬c)⇒(a∨b∨(b∧c))
    $$\neg c \Rightarrow \left(a \vee b \vee \left(b \wedge c\right)\right)$$
    Solución detallada
    $$a \vee b \vee \left(b \wedge c\right) = a \vee b$$
    $$\neg c \Rightarrow \left(a \vee b \vee \left(b \wedge c\right)\right) = a \vee b \vee c$$
    Simplificación [src]
    $$a \vee b \vee c$$ 
    a∨b∨c
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$a \vee b \vee c$$ 
    a∨b∨c
    FNCD [src]
    $$a \vee b \vee c$$ 
    a∨b∨c
    FNDP [src]
    $$a \vee b \vee c$$ 
    a∨b∨c
    FND [src]
    Ya está reducido a FND
    $$a \vee b \vee c$$ 
    a∨b∨c
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