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Expresión ¬x1¬x2¬x3∨¬x1¬x2x3∨¬x1x2x3∨x1¬x2¬x3∨x1¬x2x3

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (x1∧x3∧(¬x2))∨(x2∧x3∧(¬x1))∨(x1∧(¬x2)∧(¬x3))∨(x3∧(¬x1)∧(¬x2))∨((¬x1)∧(¬x2)∧(¬x3))
    $$\left(x_{1} \wedge x_{3} \wedge \neg x_{2}\right) \vee \left(x_{1} \wedge \neg x_{2} \wedge \neg x_{3}\right) \vee \left(x_{2} \wedge x_{3} \wedge \neg x_{1}\right) \vee \left(x_{3} \wedge \neg x_{1} \wedge \neg x_{2}\right) \vee \left(\neg x_{1} \wedge \neg x_{2} \wedge \neg x_{3}\right)$$
    Solución detallada
    $$\left(x_{1} \wedge x_{3} \wedge \neg x_{2}\right) \vee \left(x_{1} \wedge \neg x_{2} \wedge \neg x_{3}\right) \vee \left(x_{2} \wedge x_{3} \wedge \neg x_{1}\right) \vee \left(x_{3} \wedge \neg x_{1} \wedge \neg x_{2}\right) \vee \left(\neg x_{1} \wedge \neg x_{2} \wedge \neg x_{3}\right) = \left(x_{3} \wedge \neg x_{1}\right) \vee \neg x_{2}$$
    Simplificación [src]
    $$\left(x_{3} \wedge \neg x_{1}\right) \vee \neg x_{2}$$
    (¬x2)∨(x3∧(¬x1))
    Tabla de verdad
    +----+----+----+--------+
    | x1 | x2 | x3 | result |
    +====+====+====+========+
    | 0  | 0  | 0  | 1      |
    +----+----+----+--------+
    | 0  | 0  | 1  | 1      |
    +----+----+----+--------+
    | 0  | 1  | 0  | 0      |
    +----+----+----+--------+
    | 0  | 1  | 1  | 1      |
    +----+----+----+--------+
    | 1  | 0  | 0  | 1      |
    +----+----+----+--------+
    | 1  | 0  | 1  | 1      |
    +----+----+----+--------+
    | 1  | 1  | 0  | 0      |
    +----+----+----+--------+
    | 1  | 1  | 1  | 0      |
    +----+----+----+--------+
    FNDP [src]
    $$\left(x_{3} \wedge \neg x_{1}\right) \vee \neg x_{2}$$
    (¬x2)∨(x3∧(¬x1))
    FNC [src]
    $$\left(x_{3} \vee \neg x_{2}\right) \wedge \left(\neg x_{1} \vee \neg x_{2}\right)$$
    (x3∨(¬x2))∧((¬x1)∨(¬x2))
    FND [src]
    Ya está reducido a FND
    $$\left(x_{3} \wedge \neg x_{1}\right) \vee \neg x_{2}$$
    (¬x2)∨(x3∧(¬x1))
    FNCD [src]
    $$\left(x_{3} \vee \neg x_{2}\right) \wedge \left(\neg x_{1} \vee \neg x_{2}\right)$$
    (x3∨(¬x2))∧((¬x1)∨(¬x2))