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Expresión ac→((b→a)→c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧c)⇒((b⇒a)⇒c)
    $$\left(a \wedge c\right) \Rightarrow \left(\left(b \Rightarrow a\right) \Rightarrow c\right)$$
    Solución detallada
    $$b \Rightarrow a = a \vee \neg b$$
    $$\left(b \Rightarrow a\right) \Rightarrow c = c \vee \left(b \wedge \neg a\right)$$
    $$\left(a \wedge c\right) \Rightarrow \left(\left(b \Rightarrow a\right) \Rightarrow c\right) = 1$$
    Simplificación [src]
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    1
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    1
    1
    FNCD [src]
    1
    1
    FNDP [src]
    1
    1
    FNC [src]
    Ya está reducido a FNC
    1
    1