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Expresión ac⇒((b⇒a)⇒c)
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Solución
Ha introducido
[src]
(a∧c)⇒((b⇒a)⇒c)
$$\left(a \wedge c\right) \Rightarrow \left(\left(b \Rightarrow a\right) \Rightarrow c\right)$$
Solución detallada
$$b \Rightarrow a = a \vee \neg b$$
$$\left(b \Rightarrow a\right) \Rightarrow c = c \vee \left(b \wedge \neg a\right)$$
$$\left(a \wedge c\right) \Rightarrow \left(\left(b \Rightarrow a\right) \Rightarrow c\right) = 1$$
$$\left(b \Rightarrow a\right) \Rightarrow c = c \vee \left(b \wedge \neg a\right)$$
$$\left(a \wedge c\right) \Rightarrow \left(\left(b \Rightarrow a\right) \Rightarrow c\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+