Expresión не(a)&не(b)&cva&не(b)&не(c)va&не(b)&c
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\left(a \wedge c \wedge \neg b\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(c \wedge \neg a \wedge \neg b\right) = \neg b \wedge \left(a \vee c\right)$$
$$\neg b \wedge \left(a \vee c\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
$$\left(a \wedge \neg b\right) \vee \left(c \wedge \neg b\right)$$
$$\left(a \wedge \neg b\right) \vee \left(c \wedge \neg b\right)$$
Ya está reducido a FNC
$$\neg b \wedge \left(a \vee c\right)$$
$$\neg b \wedge \left(a \vee c\right)$$