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Lógica matemática/ ¬(A∨B)⇒(C⊕A)

Expresión ¬(A∨B)⇒(C⊕A)

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    Solución

    Ha introducido [src] 
    (¬(a∨b))⇒(a⊕c)
    $$\neg \left(a \vee b\right) \Rightarrow \left(a ⊕ c\right)$$
    Solución detallada
    $$\neg \left(a \vee b\right) = \neg a \wedge \neg b$$
    $$a ⊕ c = \left(a \wedge \neg c\right) \vee \left(c \wedge \neg a\right)$$
    $$\neg \left(a \vee b\right) \Rightarrow \left(a ⊕ c\right) = a \vee b \vee c$$
    Simplificación [src]
    $$a \vee b \vee c$$ 
    a∨b∨c
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$a \vee b \vee c$$ 
    a∨b∨c
    FNDP [src]
    $$a \vee b \vee c$$ 
    a∨b∨c
    FNCD [src]
    $$a \vee b \vee c$$ 
    a∨b∨c
    FNC [src]
    Ya está reducido a FNC
    $$a \vee b \vee c$$ 
    a∨b∨c
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