Expresión ABCvAB!CvA!BCvA!B!Cv!ABC
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∧b∧c)∨(a∧b∧¬c)∨(a∧c∧¬b)∨(a∧¬b∧¬c)∨(b∧c∧¬a)=a∨(b∧c)
a∨(b∧c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(a∨b)∧(a∨c)
a∨(b∧c)
(a∨b)∧(a∨c)
Ya está reducido a FND
a∨(b∧c)