Sr Examen
Expresión Av(B&C)=(AvB)&(AvC).
El profesor se sorprenderá mucho al ver tu solución correcta😉
⌨
Solución
Ha introducido
[src]
(a∨(b∧c))⇔((a∨b)∧(a∨c))
$$\left(\left(a \vee b\right) \wedge \left(a \vee c\right)\right) ⇔ \left(a \vee \left(b \wedge c\right)\right)$$
Solución detallada
$$\left(a \vee b\right) \wedge \left(a \vee c\right) = a \vee \left(b \wedge c\right)$$
$$\left(\left(a \vee b\right) \wedge \left(a \vee c\right)\right) ⇔ \left(a \vee \left(b \wedge c\right)\right) = 1$$
$$\left(\left(a \vee b\right) \wedge \left(a \vee c\right)\right) ⇔ \left(a \vee \left(b \wedge c\right)\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+