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Lógica matemática/ DCB+D¬CBA

Expresión DCB+D¬CBA

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    Solución

    Ha introducido [src] 
    (b∧c∧d)∨(a∧b∧d∧(¬c))
    $$\left(b \wedge c \wedge d\right) \vee \left(a \wedge b \wedge d \wedge \neg c\right)$$
    Solución detallada
    $$\left(b \wedge c \wedge d\right) \vee \left(a \wedge b \wedge d \wedge \neg c\right) = b \wedge d \wedge \left(a \vee c\right)$$
    Simplificación [src]
    $$b \wedge d \wedge \left(a \vee c\right)$$ 
    b∧d∧(a∨c)
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FNCD [src]
    $$b \wedge d \wedge \left(a \vee c\right)$$ 
    b∧d∧(a∨c)
    FND [src]
    $$\left(a \wedge b \wedge d\right) \vee \left(b \wedge c \wedge d\right)$$ 
    (a∧b∧d)∨(b∧c∧d)
    FNC [src]
    Ya está reducido a FNC
    $$b \wedge d \wedge \left(a \vee c\right)$$ 
    b∧d∧(a∨c)
    FNDP [src]
    $$\left(a \wedge b \wedge d\right) \vee \left(b \wedge c \wedge d\right)$$ 
    (a∧b∧d)∨(b∧c∧d)
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