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Lógica matemática/ ¬A∧((A∨B)∨(A∨C))

Expresión ¬A∧((A∨B)∨(A∨C))

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    Solución

    Ha introducido [src] 
    (¬a)∧(a∨b∨c)
    $$\neg a \wedge \left(a \vee b \vee c\right)$$
    Solución detallada
    $$\neg a \wedge \left(a \vee b \vee c\right) = \neg a \wedge \left(b \vee c\right)$$
    Simplificación [src]
    $$\neg a \wedge \left(b \vee c\right)$$ 
    (¬a)∧(b∨c)
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 0      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 0      |
+---+---+---+--------+
    FNCD [src]
    $$\neg a \wedge \left(b \vee c\right)$$ 
    (¬a)∧(b∨c)
    FNDP [src]
    $$\left(b \wedge \neg a\right) \vee \left(c \wedge \neg a\right)$$ 
    (b∧(¬a))∨(c∧(¬a))
    FNC [src]
    Ya está reducido a FNC
    $$\neg a \wedge \left(b \vee c\right)$$ 
    (¬a)∧(b∨c)
    FND [src]
    $$\left(b \wedge \neg a\right) \vee \left(c \wedge \neg a\right)$$ 
    (b∧(¬a))∨(c∧(¬a))
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