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Expresión А∧В∨(С∨¬А∨А∧С)∧¬В

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧b)∨((¬b)∧(c∨(¬a)∨(a∧c)))
    $$\left(a \wedge b\right) \vee \left(\neg b \wedge \left(c \vee \left(a \wedge c\right) \vee \neg a\right)\right)$$
    Solución detallada
    $$c \vee \left(a \wedge c\right) \vee \neg a = c \vee \neg a$$
    $$\neg b \wedge \left(c \vee \left(a \wedge c\right) \vee \neg a\right) = \neg b \wedge \left(c \vee \neg a\right)$$
    $$\left(a \wedge b\right) \vee \left(\neg b \wedge \left(c \vee \left(a \wedge c\right) \vee \neg a\right)\right) = \left(a \wedge b\right) \vee \left(c \wedge \neg b\right) \vee \left(\neg a \wedge \neg b\right)$$
    Simplificación [src]
    $$\left(a \wedge b\right) \vee \left(c \wedge \neg b\right) \vee \left(\neg a \wedge \neg b\right)$$
    (a∧b)∨(c∧(¬b))∨((¬a)∧(¬b))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    $$\left(a \vee \neg b\right) \wedge \left(b \vee \neg b\right) \wedge \left(a \vee c \vee \neg a\right) \wedge \left(a \vee c \vee \neg b\right) \wedge \left(a \vee \neg a \vee \neg b\right) \wedge \left(b \vee c \vee \neg a\right) \wedge \left(b \vee c \vee \neg b\right) \wedge \left(b \vee \neg a \vee \neg b\right)$$
    (a∨(¬b))∧(b∨(¬b))∧(a∨c∨(¬a))∧(a∨c∨(¬b))∧(b∨c∨(¬a))∧(b∨c∨(¬b))∧(a∨(¬a)∨(¬b))∧(b∨(¬a)∨(¬b))
    FND [src]
    Ya está reducido a FND
    $$\left(a \wedge b\right) \vee \left(c \wedge \neg b\right) \vee \left(\neg a \wedge \neg b\right)$$
    (a∧b)∨(c∧(¬b))∨((¬a)∧(¬b))
    FNDP [src]
    $$\left(a \wedge b\right) \vee \left(c \wedge \neg b\right) \vee \left(\neg a \wedge \neg b\right)$$
    (a∧b)∨(c∧(¬b))∨((¬a)∧(¬b))
    FNCD [src]
    $$\left(a \vee \neg b\right) \wedge \left(b \vee c \vee \neg a\right)$$
    (a∨(¬b))∧(b∨c∨(¬a))