Expresión А∧В∨(С∨¬А∨А∧С)∧¬В
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Solución
Solución detallada
$$c \vee \left(a \wedge c\right) \vee \neg a = c \vee \neg a$$
$$\neg b \wedge \left(c \vee \left(a \wedge c\right) \vee \neg a\right) = \neg b \wedge \left(c \vee \neg a\right)$$
$$\left(a \wedge b\right) \vee \left(\neg b \wedge \left(c \vee \left(a \wedge c\right) \vee \neg a\right)\right) = \left(a \wedge b\right) \vee \left(c \wedge \neg b\right) \vee \left(\neg a \wedge \neg b\right)$$
$$\left(a \wedge b\right) \vee \left(c \wedge \neg b\right) \vee \left(\neg a \wedge \neg b\right)$$
(a∧b)∨(c∧(¬b))∨((¬a)∧(¬b))
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(a \vee \neg b\right) \wedge \left(b \vee \neg b\right) \wedge \left(a \vee c \vee \neg a\right) \wedge \left(a \vee c \vee \neg b\right) \wedge \left(a \vee \neg a \vee \neg b\right) \wedge \left(b \vee c \vee \neg a\right) \wedge \left(b \vee c \vee \neg b\right) \wedge \left(b \vee \neg a \vee \neg b\right)$$
(a∨(¬b))∧(b∨(¬b))∧(a∨c∨(¬a))∧(a∨c∨(¬b))∧(b∨c∨(¬a))∧(b∨c∨(¬b))∧(a∨(¬a)∨(¬b))∧(b∨(¬a)∨(¬b))
Ya está reducido a FND
$$\left(a \wedge b\right) \vee \left(c \wedge \neg b\right) \vee \left(\neg a \wedge \neg b\right)$$
(a∧b)∨(c∧(¬b))∨((¬a)∧(¬b))
$$\left(a \wedge b\right) \vee \left(c \wedge \neg b\right) \vee \left(\neg a \wedge \neg b\right)$$
(a∧b)∨(c∧(¬b))∨((¬a)∧(¬b))
$$\left(a \vee \neg b\right) \wedge \left(b \vee c \vee \neg a\right)$$