Sr Examen
Expresión ¬x∧z∨x∧y∨x∧¬z
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(x∧y)∨(x∧(¬z))∨(z∧(¬x))
$$\left(x \wedge y\right) \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$
Simplificación
[src]
$$\left(x \wedge y\right) \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$
(x∧y)∨(x∧(¬z))∨(z∧(¬x))
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+
FNCD
[src]
$$\left(x \vee z\right) \wedge \left(y \vee \neg x \vee \neg z\right)$$
(x∨z)∧(y∨(¬x)∨(¬z))
FND
[src]
Ya está reducido a FND
$$\left(x \wedge y\right) \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$
(x∧y)∨(x∧(¬z))∨(z∧(¬x))
FNDP
[src]
$$\left(x \wedge y\right) \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$
(x∧y)∨(x∧(¬z))∨(z∧(¬x))
FNC
[src]
$$\left(x \vee z\right) \wedge \left(x \vee \neg x\right) \wedge \left(x \vee y \vee z\right) \wedge \left(x \vee y \vee \neg x\right) \wedge \left(x \vee z \vee \neg z\right) \wedge \left(x \vee \neg x \vee \neg z\right) \wedge \left(y \vee z \vee \neg z\right) \wedge \left(y \vee \neg x \vee \neg z\right)$$
(x∨z)∧(x∨(¬x))∧(x∨y∨z)∧(x∨y∨(¬x))∧(x∨z∨(¬z))∧(y∨z∨(¬z))∧(x∨(¬x)∨(¬z))∧(y∨(¬x)∨(¬z))