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Lógica matemática/ CA+C¬B+BA+CB

Expresión CA+C¬B+BA+CB

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    Solución

    Ha introducido [src] 
    (a∧b)∨(a∧c)∨(b∧c)∨(c∧(¬b))
    (a∧b)∨(a∧c)∨(b∧c)∨(c∧¬b)\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(b \wedge c\right) \vee \left(c \wedge \neg b\right)
    Solución detallada
    (a∧b)∨(a∧c)∨(b∧c)∨(c∧¬b)=c∨(a∧b)\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(b \wedge c\right) \vee \left(c \wedge \neg b\right) = c \vee \left(a \wedge b\right)
    Simplificación [src]
    c∨(a∧b)c \vee \left(a \wedge b\right) 
    c∨(a∧b)
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNDP [src]
    c∨(a∧b)c \vee \left(a \wedge b\right) 
    c∨(a∧b)
    FND [src]
    Ya está reducido a FND
    c∨(a∧b)c \vee \left(a \wedge b\right) 
    c∨(a∧b)
    FNC [src]
    (a∨c)∧(b∨c)\left(a \vee c\right) \wedge \left(b \vee c\right) 
    (a∨c)∧(b∨c)
    FNCD [src]
    (a∨c)∧(b∨c)\left(a \vee c\right) \wedge \left(b \vee c\right) 
    (a∨c)∧(b∨c)
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