Expresión xzv((w⇒x)~(z⇒y))
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
w⇒x=x∨¬wz⇒y=y∨¬z(w⇒x)⇔(z⇒y)=(x∧y)∨(x∧¬z)∨(y∧¬w)∨(¬w∧¬z)∨(w∧z∧¬x∧¬y)(x∧z)∨((w⇒x)⇔(z⇒y))=x∨(y∧¬w)∨(¬w∧¬z)∨(w∧z∧¬y)
x∨(y∧¬w)∨(¬w∧¬z)∨(w∧z∧¬y)
x∨(y∧(¬w))∨((¬w)∧(¬z))∨(w∧z∧(¬y))
Tabla de verdad
+---+---+---+---+--------+
| w | x | y | z | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
(w∨x∨¬w)∧(x∨z∨¬w)∧(x∨¬w∨¬y)∧(w∨x∨y∨¬w)∧(w∨x∨y∨¬z)∧(w∨x∨¬w∨¬z)∧(x∨y∨z∨¬w)∧(x∨y∨z∨¬z)∧(x∨y∨¬w∨¬y)∧(x∨y∨¬y∨¬z)∧(x∨z∨¬w∨¬z)∧(x∨¬w∨¬y∨¬z)
(w∨x∨(¬w))∧(x∨z∨(¬w))∧(x∨(¬w)∨(¬y))∧(w∨x∨y∨(¬w))∧(w∨x∨y∨(¬z))∧(x∨y∨z∨(¬w))∧(x∨y∨z∨(¬z))∧(w∨x∨(¬w)∨(¬z))∧(x∨y∨(¬w)∨(¬y))∧(x∨y∨(¬y)∨(¬z))∧(x∨z∨(¬w)∨(¬z))∧(x∨(¬w)∨(¬y)∨(¬z))
x∨(y∧¬w)∨(¬w∧¬z)∨(w∧z∧¬y)
x∨(y∧(¬w))∨((¬w)∧(¬z))∨(w∧z∧(¬y))
(x∨z∨¬w)∧(x∨¬w∨¬y)∧(w∨x∨y∨¬z)
(x∨z∨(¬w))∧(x∨(¬w)∨(¬y))∧(w∨x∨y∨(¬z))
Ya está reducido a FND
x∨(y∧¬w)∨(¬w∧¬z)∨(w∧z∧¬y)
x∨(y∧(¬w))∨((¬w)∧(¬z))∨(w∧z∧(¬y))