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Lógica matemática/ (¬av¬bvcvd)(¬av¬bvcv¬d)(¬av¬bv¬cvd)

Expresión (¬av¬bvcvd)(¬av¬bvcv¬d)(¬av¬bv¬cvd)

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    (c∨d∨(¬a)∨(¬b))∧(c∨(¬a)∨(¬b)∨(¬d))∧(d∨(¬a)∨(¬b)∨(¬c))
    $$\left(c \vee d \vee \neg a \vee \neg b\right) \wedge \left(c \vee \neg a \vee \neg b \vee \neg d\right) \wedge \left(d \vee \neg a \vee \neg b \vee \neg c\right)$$
    Solución detallada
    $$\left(c \vee d \vee \neg a \vee \neg b\right) \wedge \left(c \vee \neg a \vee \neg b \vee \neg d\right) \wedge \left(d \vee \neg a \vee \neg b \vee \neg c\right) = \left(c \wedge d\right) \vee \neg a \vee \neg b$$
    Simplificación [src]
    $$\left(c \wedge d\right) \vee \neg a \vee \neg b$$ 
    (¬a)∨(¬b)∨(c∧d)
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FNC [src]
    $$\left(c \vee \neg a \vee \neg b\right) \wedge \left(d \vee \neg a \vee \neg b\right)$$ 
    (c∨(¬a)∨(¬b))∧(d∨(¬a)∨(¬b))
    FNDP [src]
    $$\left(c \wedge d\right) \vee \neg a \vee \neg b$$ 
    (¬a)∨(¬b)∨(c∧d)
    FNCD [src]
    $$\left(c \vee \neg a \vee \neg b\right) \wedge \left(d \vee \neg a \vee \neg b\right)$$ 
    (c∨(¬a)∨(¬b))∧(d∨(¬a)∨(¬b))
    FND [src]
    Ya está reducido a FND
    $$\left(c \wedge d\right) \vee \neg a \vee \neg b$$ 
    (¬a)∨(¬b)∨(c∧d)
    © Sr Examen