Sr Examen
Expresión bv(¬a⇔c)&a
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Solución
Solución detallada
$$c ⇔ \neg a = \left(a \wedge \neg c\right) \vee \left(c \wedge \neg a\right)$$
$$a \wedge \left(c ⇔ \neg a\right) = a \wedge \neg c$$
$$b \vee \left(a \wedge \left(c ⇔ \neg a\right)\right) = b \vee \left(a \wedge \neg c\right)$$
$$a \wedge \left(c ⇔ \neg a\right) = a \wedge \neg c$$
$$b \vee \left(a \wedge \left(c ⇔ \neg a\right)\right) = b \vee \left(a \wedge \neg c\right)$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+