Expresión abvac
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∧b)∨(a∧c)=a∧(b∨c)
a∧(b∨c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(a∧b)∨(a∧c)
Ya está reducido a FNC
a∧(b∨c)
a∧(b∨c)
(a∧b)∨(a∧c)