Sr Examen

Expresión –av–b&c

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    Solución

    Ha introducido [src]
    (¬a)∨(c∧(¬b))
    $$\left(c \wedge \neg b\right) \vee \neg a$$
    Simplificación [src]
    $$\left(c \wedge \neg b\right) \vee \neg a$$
    (¬a)∨(c∧(¬b))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNCD [src]
    $$\left(c \vee \neg a\right) \wedge \left(\neg a \vee \neg b\right)$$
    (c∨(¬a))∧((¬a)∨(¬b))
    FND [src]
    Ya está reducido a FND
    $$\left(c \wedge \neg b\right) \vee \neg a$$
    (¬a)∨(c∧(¬b))
    FNDP [src]
    $$\left(c \wedge \neg b\right) \vee \neg a$$
    (¬a)∨(c∧(¬b))
    FNC [src]
    $$\left(c \vee \neg a\right) \wedge \left(\neg a \vee \neg b\right)$$
    (c∨(¬a))∧((¬a)∨(¬b))