Expresión AB'+A'BC+A'B'C
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Solución
Solución detallada
$$\neg \left(a \wedge b\right) = \neg a \vee \neg b$$
$$\neg \left(a \vee \left(b \wedge c\right)\right) = \neg a \wedge \left(\neg b \vee \neg c\right)$$
$$c \wedge \neg a \wedge \neg b \wedge \neg \left(a \vee \left(b \wedge c\right)\right) = c \wedge \neg a \wedge \neg b$$
$$\left(c \wedge \neg a \wedge \neg b \wedge \neg \left(a \vee \left(b \wedge c\right)\right)\right) \vee \neg \left(a \wedge b\right) = \neg a \vee \neg b$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
Ya está reducido a FND
$$\neg a \vee \neg b$$
Ya está reducido a FNC
$$\neg a \vee \neg b$$