Sr Examen

Expresión acv¬b¬c

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧c)∨((¬b)∧(¬c))
    $$\left(a \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    Simplificación [src]
    $$\left(a \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    (a∧c)∨((¬b)∧(¬c))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    $$\left(a \vee \neg b\right) \wedge \left(a \vee \neg c\right) \wedge \left(c \vee \neg b\right) \wedge \left(c \vee \neg c\right)$$
    (a∨(¬b))∧(a∨(¬c))∧(c∨(¬b))∧(c∨(¬c))
    FNDP [src]
    $$\left(a \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    (a∧c)∨((¬b)∧(¬c))
    FNCD [src]
    $$\left(a \vee \neg c\right) \wedge \left(c \vee \neg b\right)$$
    (a∨(¬c))∧(c∨(¬b))
    FND [src]
    Ya está reducido a FND
    $$\left(a \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    (a∧c)∨((¬b)∧(¬c))