Sr Examen
Expresión (A⊕¬C)⊕(A∨D)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Solución detallada
$$a ⊕ \neg c ⊕ \left(a \vee d\right) = \left(a \wedge \neg c\right) \vee \left(\neg c \wedge \neg d\right) \vee \left(c \wedge d \wedge \neg a\right)$$
Simplificación
[src]
$$\left(a \wedge \neg c\right) \vee \left(\neg c \wedge \neg d\right) \vee \left(c \wedge d \wedge \neg a\right)$$
(a∧(¬c))∨((¬c)∧(¬d))∨(c∧d∧(¬a))
Tabla de verdad
+---+---+---+--------+ | a | c | d | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+
FNC
[src]
$$\left(c \vee \neg c\right) \wedge \left(d \vee \neg c\right) \wedge \left(\neg a \vee \neg c\right) \wedge \left(a \vee c \vee \neg c\right) \wedge \left(a \vee c \vee \neg d\right) \wedge \left(a \vee d \vee \neg c\right) \wedge \left(a \vee d \vee \neg d\right) \wedge \left(a \vee \neg a \vee \neg c\right) \wedge \left(a \vee \neg a \vee \neg d\right) \wedge \left(c \vee \neg c \vee \neg d\right) \wedge \left(d \vee \neg c \vee \neg d\right) \wedge \left(\neg a \vee \neg c \vee \neg d\right)$$
(c∨(¬c))∧(d∨(¬c))∧((¬a)∨(¬c))∧(a∨c∨(¬c))∧(a∨c∨(¬d))∧(a∨d∨(¬c))∧(a∨d∨(¬d))∧(a∨(¬a)∨(¬c))∧(a∨(¬a)∨(¬d))∧(c∨(¬c)∨(¬d))∧(d∨(¬c)∨(¬d))∧((¬a)∨(¬c)∨(¬d))
FND
[src]
Ya está reducido a FND
$$\left(a \wedge \neg c\right) \vee \left(\neg c \wedge \neg d\right) \vee \left(c \wedge d \wedge \neg a\right)$$
(a∧(¬c))∨((¬c)∧(¬d))∨(c∧d∧(¬a))
FNDP
[src]
$$\left(a \wedge \neg c\right) \vee \left(\neg c \wedge \neg d\right) \vee \left(c \wedge d \wedge \neg a\right)$$
(a∧(¬c))∨((¬c)∧(¬d))∨(c∧d∧(¬a))
FNCD
[src]
$$\left(d \vee \neg c\right) \wedge \left(\neg a \vee \neg c\right) \wedge \left(a \vee c \vee \neg d\right)$$
(d∨(¬c))∧((¬a)∨(¬c))∧(a∨c∨(¬d))