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Expresión (P∧Q)∨(¬P∧Q)∨(Q∧R)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (p∧q)∨(q∧r)∨(q∧(¬p))
    $$\left(p \wedge q\right) \vee \left(q \wedge r\right) \vee \left(q \wedge \neg p\right)$$
    Solución detallada
    $$\left(p \wedge q\right) \vee \left(q \wedge r\right) \vee \left(q \wedge \neg p\right) = q$$
    Simplificación [src]
    $$q$$
    q
    Tabla de verdad
    +---+---+---+--------+
    | p | q | r | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$q$$
    q
    FNDP [src]
    $$q$$
    q
    FNC [src]
    Ya está reducido a FNC
    $$q$$
    q
    FNCD [src]
    $$q$$
    q