Sr Examen
Expresión ¬(A⇒B)∧¬((A∧B)⇒(A∧B))
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Solución
Ha introducido
[src]
(¬(a⇒b))∧(¬((a∧b)⇒(a∧b)))
$$a \not\Rightarrow b \wedge \left(a \wedge b\right) \not\Rightarrow \left(a \wedge b\right)$$
Solución detallada
$$a \Rightarrow b = b \vee \neg a$$
$$a \not\Rightarrow b = a \wedge \neg b$$
$$\left(a \wedge b\right) \Rightarrow \left(a \wedge b\right) = 1$$
$$\left(a \wedge b\right) \not\Rightarrow \left(a \wedge b\right) = \text{False}$$
$$a \not\Rightarrow b \wedge \left(a \wedge b\right) \not\Rightarrow \left(a \wedge b\right) = \text{False}$$
$$a \not\Rightarrow b = a \wedge \neg b$$
$$\left(a \wedge b\right) \Rightarrow \left(a \wedge b\right) = 1$$
$$\left(a \wedge b\right) \not\Rightarrow \left(a \wedge b\right) = \text{False}$$
$$a \not\Rightarrow b \wedge \left(a \wedge b\right) \not\Rightarrow \left(a \wedge b\right) = \text{False}$$
Tabla de verdad
+---+---+--------+ | a | b | result | +===+===+========+ | 0 | 0 | 0 | +---+---+--------+ | 0 | 1 | 0 | +---+---+--------+ | 1 | 0 | 0 | +---+---+--------+ | 1 | 1 | 0 | +---+---+--------+