Sr Examen

Expresión (P∧Q)∨(¬P∧R)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (p∧q)∨(r∧(¬p))
    $$\left(p \wedge q\right) \vee \left(r \wedge \neg p\right)$$
    Simplificación [src]
    $$\left(p \wedge q\right) \vee \left(r \wedge \neg p\right)$$
    (p∧q)∨(r∧(¬p))
    Tabla de verdad
    +---+---+---+--------+
    | p | q | r | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    $$\left(p \vee r\right) \wedge \left(p \vee \neg p\right) \wedge \left(q \vee r\right) \wedge \left(q \vee \neg p\right)$$
    (p∨r)∧(q∨r)∧(p∨(¬p))∧(q∨(¬p))
    FND [src]
    Ya está reducido a FND
    $$\left(p \wedge q\right) \vee \left(r \wedge \neg p\right)$$
    (p∧q)∨(r∧(¬p))
    FNDP [src]
    $$\left(p \wedge q\right) \vee \left(r \wedge \neg p\right)$$
    (p∧q)∨(r∧(¬p))
    FNCD [src]
    $$\left(p \vee r\right) \wedge \left(q \vee \neg p\right)$$
    (p∨r)∧(q∨(¬p))