Sr Examen
Expresión ¬a&¬b&¬cv¬a&¬b&cv¬a&b&cva&¬b&¬cva&¬b&cva&b&¬c
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(a∧b∧(¬c))∨(a∧c∧(¬b))∨(b∧c∧(¬a))∨(a∧(¬b)∧(¬c))∨(c∧(¬a)∧(¬b))∨((¬a)∧(¬b)∧(¬c))
$$\left(a \wedge b \wedge \neg c\right) \vee \left(a \wedge c \wedge \neg b\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(b \wedge c \wedge \neg a\right) \vee \left(c \wedge \neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right)$$
Solución detallada
$$\left(a \wedge b \wedge \neg c\right) \vee \left(a \wedge c \wedge \neg b\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(b \wedge c \wedge \neg a\right) \vee \left(c \wedge \neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right) = \left(a \wedge \neg c\right) \vee \left(c \wedge \neg a\right) \vee \neg b$$
Simplificación
[src]
$$\left(a \wedge \neg c\right) \vee \left(c \wedge \neg a\right) \vee \neg b$$
(¬b)∨(a∧(¬c))∨(c∧(¬a))
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+
FNDP
[src]
$$\left(a \wedge \neg c\right) \vee \left(c \wedge \neg a\right) \vee \neg b$$
(¬b)∨(a∧(¬c))∨(c∧(¬a))
FND
[src]
Ya está reducido a FND
$$\left(a \wedge \neg c\right) \vee \left(c \wedge \neg a\right) \vee \neg b$$
(¬b)∨(a∧(¬c))∨(c∧(¬a))
FNC
[src]
$$\left(a \vee c \vee \neg b\right) \wedge \left(a \vee \neg a \vee \neg b\right) \wedge \left(c \vee \neg b \vee \neg c\right) \wedge \left(\neg a \vee \neg b \vee \neg c\right)$$
(a∨c∨(¬b))∧(a∨(¬a)∨(¬b))∧(c∨(¬b)∨(¬c))∧((¬a)∨(¬b)∨(¬c))
FNCD
[src]
$$\left(a \vee c \vee \neg b\right) \wedge \left(\neg a \vee \neg b \vee \neg c\right)$$
(a∨c∨(¬b))∧((¬a)∨(¬b)∨(¬c))