Expresión (R∧G)∨H→~R
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(h∨(g∧r))⇒¬r=(¬g∧¬h)∨¬r
(¬g∧¬h)∨¬r
Tabla de verdad
+---+---+---+--------+
| g | h | r | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
(¬g∧¬h)∨¬r
(¬g∨¬r)∧(¬h∨¬r)
Ya está reducido a FND
(¬g∧¬h)∨¬r
(¬g∨¬r)∧(¬h∨¬r)