Sr Examen

Expresión notpv(q&r)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (¬p)∨(q∧r)
    $$\left(q \wedge r\right) \vee \neg p$$
    Simplificación [src]
    $$\left(q \wedge r\right) \vee \neg p$$
    (¬p)∨(q∧r)
    Tabla de verdad
    +---+---+---+--------+
    | p | q | r | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    $$\left(q \vee \neg p\right) \wedge \left(r \vee \neg p\right)$$
    (q∨(¬p))∧(r∨(¬p))
    FND [src]
    Ya está reducido a FND
    $$\left(q \wedge r\right) \vee \neg p$$
    (¬p)∨(q∧r)
    FNCD [src]
    $$\left(q \vee \neg p\right) \wedge \left(r \vee \neg p\right)$$
    (q∨(¬p))∧(r∨(¬p))
    FNDP [src]
    $$\left(q \wedge r\right) \vee \neg p$$
    (¬p)∨(q∧r)