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Expresión avb⇒((a⇒c)&(b⇒d)⇒cvd)

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    Solución

    Ha introducido [src]
    (a∨b)⇒(((a⇒c)∧(b⇒d))⇒(c∨d))
    $$\left(a \vee b\right) \Rightarrow \left(\left(\left(a \Rightarrow c\right) \wedge \left(b \Rightarrow d\right)\right) \Rightarrow \left(c \vee d\right)\right)$$
    Solución detallada
    $$a \Rightarrow c = c \vee \neg a$$
    $$b \Rightarrow d = d \vee \neg b$$
    $$\left(a \Rightarrow c\right) \wedge \left(b \Rightarrow d\right) = \left(c \wedge d\right) \vee \left(c \wedge \neg b\right) \vee \left(d \wedge \neg a\right) \vee \left(\neg a \wedge \neg b\right)$$
    $$\left(\left(a \Rightarrow c\right) \wedge \left(b \Rightarrow d\right)\right) \Rightarrow \left(c \vee d\right) = a \vee b \vee c \vee d$$
    $$\left(a \vee b\right) \Rightarrow \left(\left(\left(a \Rightarrow c\right) \wedge \left(b \Rightarrow d\right)\right) \Rightarrow \left(c \vee d\right)\right) = 1$$
    Simplificación [src]
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    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    1
    1
    FNCD [src]
    1
    1
    FND [src]
    Ya está reducido a FND
    1
    1
    FNDP [src]
    1
    1