Sr Examen

Expresión a(c-b)-b(c-a)+c(b-a)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧(c|b))|((b∧(c|a))∨(c∧(b|a)))
    $$\left(a \wedge \left(c | b\right)\right) | \left(\left(b \wedge \left(c | a\right)\right) \vee \left(c \wedge \left(b | a\right)\right)\right)$$
    Solución detallada
    $$c | b = \neg b \vee \neg c$$
    $$a \wedge \left(c | b\right) = a \wedge \left(\neg b \vee \neg c\right)$$
    $$c | a = \neg a \vee \neg c$$
    $$b \wedge \left(c | a\right) = b \wedge \left(\neg a \vee \neg c\right)$$
    $$b | a = \neg a \vee \neg b$$
    $$c \wedge \left(b | a\right) = c \wedge \left(\neg a \vee \neg b\right)$$
    $$\left(b \wedge \left(c | a\right)\right) \vee \left(c \wedge \left(b | a\right)\right) = \left(b \wedge \neg a\right) \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$
    $$\left(a \wedge \left(c | b\right)\right) | \left(\left(b \wedge \left(c | a\right)\right) \vee \left(c \wedge \left(b | a\right)\right)\right) = \left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right) \vee \neg a$$
    Simplificación [src]
    $$\left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right) \vee \neg a$$
    (¬a)∨(b∧c)∨((¬b)∧(¬c))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    $$\left(b \vee \neg a \vee \neg b\right) \wedge \left(b \vee \neg a \vee \neg c\right) \wedge \left(c \vee \neg a \vee \neg b\right) \wedge \left(c \vee \neg a \vee \neg c\right)$$
    (b∨(¬a)∨(¬b))∧(b∨(¬a)∨(¬c))∧(c∨(¬a)∨(¬b))∧(c∨(¬a)∨(¬c))
    FND [src]
    Ya está reducido a FND
    $$\left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right) \vee \neg a$$
    (¬a)∨(b∧c)∨((¬b)∧(¬c))
    FNCD [src]
    $$\left(b \vee \neg a \vee \neg c\right) \wedge \left(c \vee \neg a \vee \neg b\right)$$
    (b∨(¬a)∨(¬c))∧(c∨(¬a)∨(¬b))
    FNDP [src]
    $$\left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right) \vee \neg a$$
    (¬a)∨(b∧c)∨((¬b)∧(¬c))