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Expresión A(B⇔С↓)∨A(B⇔С)∨A↓(B↓∨С↓)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∨(a∧(b⇔c))∨(a∧((b⇔c))))↓((b)∨(c))
    $$\left(a \vee \left(a \wedge \left(b ⇔ c\right)\right) \vee \left(a \wedge \left(\left(b ⇔ c\right)\right)\right)\right) ↓ \left(\left(b\right) \vee \left(c\right)\right)$$
    Solución detallada
    $$b ⇔ c = \left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    $$a \wedge \left(b ⇔ c\right) = a \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg b\right)$$
    $$\left(b ⇔ c\right) = \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$
    $$a \wedge \left(\left(b ⇔ c\right)\right) = a \wedge \left(b \vee c\right) \wedge \left(\neg b \vee \neg c\right)$$
    $$a \vee \left(a \wedge \left(b ⇔ c\right)\right) \vee \left(a \wedge \left(\left(b ⇔ c\right)\right)\right) = a$$
    $$b = \neg b$$
    $$c = \neg c$$
    $$\left(b\right) \vee \left(c\right) = \neg b \vee \neg c$$
    $$\left(a \vee \left(a \wedge \left(b ⇔ c\right)\right) \vee \left(a \wedge \left(\left(b ⇔ c\right)\right)\right)\right) ↓ \left(\left(b\right) \vee \left(c\right)\right) = b \wedge c \wedge \neg a$$
    Simplificación [src]
    $$b \wedge c \wedge \neg a$$
    b∧c∧(¬a)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNCD [src]
    $$b \wedge c \wedge \neg a$$
    b∧c∧(¬a)
    FNDP [src]
    $$b \wedge c \wedge \neg a$$
    b∧c∧(¬a)
    FNC [src]
    Ya está reducido a FNC
    $$b \wedge c \wedge \neg a$$
    b∧c∧(¬a)
    FND [src]
    Ya está reducido a FND
    $$b \wedge c \wedge \neg a$$
    b∧c∧(¬a)