Expresión неанебнес+неабнес+неабс+анебс+абс
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\left(a \wedge b \wedge c\right) \vee \left(a \wedge c \wedge \neg b\right) \vee \left(b \wedge c \wedge \neg a\right) \vee \left(b \wedge \neg a \wedge \neg c\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right) = \left(a \wedge c\right) \vee \left(b \wedge \neg a\right) \vee \left(\neg a \wedge \neg c\right)$$
$$\left(a \wedge c\right) \vee \left(b \wedge \neg a\right) \vee \left(\neg a \wedge \neg c\right)$$
(a∧c)∨(b∧(¬a))∨((¬a)∧(¬c))
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FND
$$\left(a \wedge c\right) \vee \left(b \wedge \neg a\right) \vee \left(\neg a \wedge \neg c\right)$$
(a∧c)∨(b∧(¬a))∨((¬a)∧(¬c))
$$\left(a \vee \neg a\right) \wedge \left(c \vee \neg a\right) \wedge \left(a \vee b \vee \neg a\right) \wedge \left(a \vee b \vee \neg c\right) \wedge \left(a \vee \neg a \vee \neg c\right) \wedge \left(b \vee c \vee \neg a\right) \wedge \left(b \vee c \vee \neg c\right) \wedge \left(c \vee \neg a \vee \neg c\right)$$
(a∨(¬a))∧(c∨(¬a))∧(a∨b∨(¬a))∧(a∨b∨(¬c))∧(b∨c∨(¬a))∧(b∨c∨(¬c))∧(a∨(¬a)∨(¬c))∧(c∨(¬a)∨(¬c))
$$\left(a \wedge c\right) \vee \left(b \wedge \neg a\right) \vee \left(\neg a \wedge \neg c\right)$$
(a∧c)∨(b∧(¬a))∨((¬a)∧(¬c))
$$\left(c \vee \neg a\right) \wedge \left(a \vee b \vee \neg c\right)$$