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Lógica matemática/ ¬c∧Bv¬DvA∧D∧¬CvB

Expresión ¬c∧Bv¬DvA∧D∧¬CvB

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    b∨(¬d)∨(b∧(¬c))∨(a∧d∧(¬c))
    b∨(b∧¬c)∨(a∧d∧¬c)∨¬db \vee \left(b \wedge \neg c\right) \vee \left(a \wedge d \wedge \neg c\right) \vee \neg d
    Solución detallada
    b∨(b∧¬c)∨(a∧d∧¬c)∨¬d=b∨(a∧¬c)∨¬db \vee \left(b \wedge \neg c\right) \vee \left(a \wedge d \wedge \neg c\right) \vee \neg d = b \vee \left(a \wedge \neg c\right) \vee \neg d
    Simplificación [src]
    b∨(a∧¬c)∨¬db \vee \left(a \wedge \neg c\right) \vee \neg d 
    b∨(¬d)∨(a∧(¬c))
    Tabla de verdad 
    +---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    b∨(a∧¬c)∨¬db \vee \left(a \wedge \neg c\right) \vee \neg d 
    b∨(¬d)∨(a∧(¬c))
    FNC [src]
    (a∨b∨¬d)∧(b∨¬c∨¬d)\left(a \vee b \vee \neg d\right) \wedge \left(b \vee \neg c \vee \neg d\right) 
    (a∨b∨(¬d))∧(b∨(¬c)∨(¬d))
    FNCD [src]
    (a∨b∨¬d)∧(b∨¬c∨¬d)\left(a \vee b \vee \neg d\right) \wedge \left(b \vee \neg c \vee \neg d\right) 
    (a∨b∨(¬d))∧(b∨(¬c)∨(¬d))
    FNDP [src]
    b∨(a∧¬c)∨¬db \vee \left(a \wedge \neg c\right) \vee \neg d 
    b∨(¬d)∨(a∧(¬c))
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