Sr Examen

Expresión (не(p)vqvr)&p

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    p∧(q∨r∨(¬p))
    p(qr¬p)p \wedge \left(q \vee r \vee \neg p\right)
    Solución detallada
    p(qr¬p)=p(qr)p \wedge \left(q \vee r \vee \neg p\right) = p \wedge \left(q \vee r\right)
    Simplificación [src]
    p(qr)p \wedge \left(q \vee r\right)
    p∧(q∨r)
    Tabla de verdad
    +---+---+---+--------+
    | p | q | r | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    (pq)(pr)\left(p \wedge q\right) \vee \left(p \wedge r\right)
    (p∧q)∨(p∧r)
    FNC [src]
    Ya está reducido a FNC
    p(qr)p \wedge \left(q \vee r\right)
    p∧(q∨r)
    FNCD [src]
    p(qr)p \wedge \left(q \vee r\right)
    p∧(q∨r)
    FND [src]
    (pq)(pr)\left(p \wedge q\right) \vee \left(p \wedge r\right)
    (p∧q)∨(p∧r)