Expresión AC(¬A¬B+C)+¬A¬C(¬A+BC)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
a∧c∧(c∨(¬a∧¬b))=a∧c¬a∧¬c∧((b∧c)∨¬a)=¬a∧¬c(a∧c∧(c∨(¬a∧¬b)))∨(¬a∧¬c∧((b∧c)∨¬a))=(a∧c)∨(¬a∧¬c)
(a∧c)∨(¬a∧¬c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(a∨¬a)∧(a∨¬c)∧(c∨¬a)∧(c∨¬c)
(a∨(¬a))∧(a∨(¬c))∧(c∨(¬a))∧(c∨(¬c))
Ya está reducido a FND
(a∧c)∨(¬a∧¬c)
(a∨¬c)∧(c∨¬a)
(a∧c)∨(¬a∧¬c)