Sr Examen

Expresión RV(!B&!P)V(!P&!B)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    r∨((¬b)∧(¬p))
    $$r \vee \left(\neg b \wedge \neg p\right)$$
    Simplificación [src]
    $$r \vee \left(\neg b \wedge \neg p\right)$$
    r∨((¬b)∧(¬p))
    Tabla de verdad
    +---+---+---+--------+
    | b | p | r | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    $$r \vee \left(\neg b \wedge \neg p\right)$$
    r∨((¬b)∧(¬p))
    FNC [src]
    $$\left(r \vee \neg b\right) \wedge \left(r \vee \neg p\right)$$
    (r∨(¬b))∧(r∨(¬p))
    FNCD [src]
    $$\left(r \vee \neg b\right) \wedge \left(r \vee \neg p\right)$$
    (r∨(¬b))∧(r∨(¬p))
    FND [src]
    Ya está reducido a FND
    $$r \vee \left(\neg b \wedge \neg p\right)$$
    r∨((¬b)∧(¬p))