Expresión ¬(x2x3x4)↔¬(x1vx2)←x3|x4⊕x1→x3⊕x4
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$x_{1} \Rightarrow x_{3} = x_{3} \vee \neg x_{1}$$
$$\neg \left(x_{2} \wedge x_{3} \wedge x_{4}\right) = \neg x_{2} \vee \neg x_{3} \vee \neg x_{4}$$
$$\neg \left(x_{1} \vee x_{2}\right) = \neg x_{1} \wedge \neg x_{2}$$
$$x_{3} \Rightarrow \neg \left(x_{1} \vee x_{2}\right) = \left(\neg x_{1} \wedge \neg x_{2}\right) \vee \neg x_{3}$$
$$\left(x_{3} \Rightarrow \neg \left(x_{1} \vee x_{2}\right)\right) ⇔ \neg \left(x_{2} \wedge x_{3} \wedge x_{4}\right) = \left(x_{2} \wedge x_{4}\right) \vee \left(\neg x_{1} \wedge \neg x_{2}\right) \vee \neg x_{3}$$
$$\left(\left(x_{3} \Rightarrow \neg \left(x_{1} \vee x_{2}\right)\right) ⇔ \neg \left(x_{2} \wedge x_{3} \wedge x_{4}\right)\right) | x_{4} = \left(x_{1} \wedge x_{3} \wedge \neg x_{2}\right) \vee \neg x_{4}$$
$$x_{4} ⊕ \left(x_{1} \Rightarrow x_{3}\right) ⊕ \left(\left(\left(x_{3} \Rightarrow \neg \left(x_{1} \vee x_{2}\right)\right) ⇔ \neg \left(x_{2} \wedge x_{3} \wedge x_{4}\right)\right) | x_{4}\right) = x_{1} \wedge \left(x_{4} \vee \neg x_{3}\right) \wedge \left(\neg x_{2} \vee \neg x_{3}\right)$$
$$x_{1} \wedge \left(x_{4} \vee \neg x_{3}\right) \wedge \left(\neg x_{2} \vee \neg x_{3}\right)$$
x1∧(x4∨(¬x3))∧((¬x2)∨(¬x3))
Tabla de verdad
+----+----+----+----+--------+
| x1 | x2 | x3 | x4 | result |
+====+====+====+====+========+
| 0 | 0 | 0 | 0 | 0 |
+----+----+----+----+--------+
| 0 | 0 | 0 | 1 | 0 |
+----+----+----+----+--------+
| 0 | 0 | 1 | 0 | 0 |
+----+----+----+----+--------+
| 0 | 0 | 1 | 1 | 0 |
+----+----+----+----+--------+
| 0 | 1 | 0 | 0 | 0 |
+----+----+----+----+--------+
| 0 | 1 | 0 | 1 | 0 |
+----+----+----+----+--------+
| 0 | 1 | 1 | 0 | 0 |
+----+----+----+----+--------+
| 0 | 1 | 1 | 1 | 0 |
+----+----+----+----+--------+
| 1 | 0 | 0 | 0 | 1 |
+----+----+----+----+--------+
| 1 | 0 | 0 | 1 | 1 |
+----+----+----+----+--------+
| 1 | 0 | 1 | 0 | 0 |
+----+----+----+----+--------+
| 1 | 0 | 1 | 1 | 1 |
+----+----+----+----+--------+
| 1 | 1 | 0 | 0 | 1 |
+----+----+----+----+--------+
| 1 | 1 | 0 | 1 | 1 |
+----+----+----+----+--------+
| 1 | 1 | 1 | 0 | 0 |
+----+----+----+----+--------+
| 1 | 1 | 1 | 1 | 0 |
+----+----+----+----+--------+
$$\left(x_{1} \wedge \neg x_{3}\right) \vee \left(x_{1} \wedge x_{4} \wedge \neg x_{2}\right)$$
$$\left(x_{1} \wedge \neg x_{3}\right) \vee \left(x_{1} \wedge x_{4} \wedge \neg x_{2}\right) \vee \left(x_{1} \wedge x_{4} \wedge \neg x_{3}\right) \vee \left(x_{1} \wedge \neg x_{2} \wedge \neg x_{3}\right)$$
(x1∧(¬x3))∨(x1∧x4∧(¬x2))∨(x1∧x4∧(¬x3))∨(x1∧(¬x2)∧(¬x3))
Ya está reducido a FNC
$$x_{1} \wedge \left(x_{4} \vee \neg x_{3}\right) \wedge \left(\neg x_{2} \vee \neg x_{3}\right)$$
x1∧(x4∨(¬x3))∧((¬x2)∨(¬x3))
$$x_{1} \wedge \left(x_{4} \vee \neg x_{3}\right) \wedge \left(\neg x_{2} \vee \neg x_{3}\right)$$
x1∧(x4∨(¬x3))∧((¬x2)∨(¬x3))